[Linux 常見問題] Use bash variables in for loop range of bash

Source From Here 
Question 
I want to print list of numbers from 1 to 100 and I use a for loop like the following: 

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1. number=100  
2. for num in {1..$number}  
3. do  
4.   echo $num  
5. done  

When I execute the command it only prints {1..100} and not the list of number from 1 to 100. 

How-To 
Yes, that's because brace-expansion occurs before parameter expansion. Either use another shell like zsh or ksh93 or use an alternative syntax: 

Standard (POSIX) sh syntax 

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1. number=10  
2. i=1  
3. while [ "$i" -le "$number" ]; do  
4.   echo "$i"  
5.   i=$(($i + 1))  
6. done  

Ksh-style for ((...)) 

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1. for ((i=1;i<=10;i++)); do  
2.   echo "$i"  
3. done  

use eval (not recommended) 

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1. number=10  
2. eval '  
3.   for i in {1..'"$number"'}; do  
4.     echo "$i"  
5.   done  
6. '  

Use the GNU seq command on systems where it's available 

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1. number=10  
2. for i in $(seq "$number"); do  
3.   echo "$i"  
4. done  

That one being less efficient as it forks and runs a new command and the shell has to reads its output from a pipe 

Avoid loops in shells. 
Using loops in a shell script are often an indication that you're not doing it right. Most probably, your code can be written some other way. 

Supplement 
* 鳥哥私房菜 - 學習 Shell Script - 迴圈 (loop) 
* Linux Shell Scripting Tutorial (LSST) v1.05r3 - for Loop 
* Tutorialspoint - Unix - Shell Loop Control