[ Bash 範例代碼 ] List logged user by date

 Source From Here

- 09-1_list_of_logged_users.sh

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1. #!/bin/bash  
2. # Author: John Lee  
3. # Date: 2021/07/25  
4. # Description: This script will list users logged in by date  
5. # Info:  
6. #   $ last | head -n 3  
7. #   root     pts/1        192.168.37.1     Sun Jul 25 00:16    gone - no logout  
8. #   root     pts/1        192.168.37.1     Sat Jul 24 18:41 - 20:33  (01:51)  
9. #   root     pts/1        192.168.37.1     Fri Jul 23 23:00 - 05:13  (06:13)  
10.   
11. # e.g.: Sun Jul 25  
12. today=`date | awk '{print $1,$2,$3}'`  
13.   
14. echo -n "Give month to search logged user(e.g: `date +'%b'`): "  
15. read month  
16. echo -n "Give day to search logged user(e.g.: `date +'%d'`): "  
17. read day  
18.   
19. if [ ! -z "$month" ] && [ ! -z "$day" ]; then  
20.   tdate="$month\s+$day\s+"  
21. else  
22.   tdate=$today  
23.   month=`date +'%b'`  
24.   day=`date +'%d'`  
25. fi  
26.   
27. echo "Search logged user on date='$month $day'"  
28. for u in `last | grep -P "${tdate}" | awk '{print $1}' | sort | uniq`  
29. do  
30.   echo "Found user '$u'"  
31. done  

Execution output:

# last | grep -P 'Mon May\s+3\s+'
root pts/1 192.168.37.1 Mon May 3 23:08 - 01:32 (02:24)
root pts/0 192.168.37.1 Mon May 3 22:18 - 03:49 (05:30)
john :0 :0 Mon May 3 22:18 - crash (13+01:54)
...

# ./09-1_list_of_logged_users.sh
Give month to search logged user(e.g: Jul): May
Give day to search logged user(e.g.: 25): 3
Search logged user on date='May 3'
Found user 'john'
Found user 'reboot'
Found user 'root'
Found user 'wtmp'