[ Python 常見問題 ] Python find first instance of non zero number in list

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Question 
I have a list like this 

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1. myList = [0.0 , 0.0, 0.0, 2.0, 2.0]  

I would like find the location of the first number in list that is not equal to zero. 

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1. myList.index(2.0)  

Works in this example but sometimes the first non zero number will be 1 or 3. Is there a fast way of doing this? 

How-To 
Use next with enumerate: 

>>> myList = [0.0 , 0.0, 0.0, 2.0, 2.0]
>>> next((i for i, x in enumerate(myList) if x), None) # x!= 0 for strict match
3 # The first index to have value with true value which means not zero

If there is not value as not zero, the None will be returned.