Source From Here
Preface
Let's say you have the following hash of people to ages:
Now, what if we want to "sort" the hash into age order? We can't. At least, not exactly. Hashes are not meant to be in a certain order (though they are in Ruby 1.9) as they're a data structure where one thing merely relates to another thing. The relationships themselves are not elements of data in themselves.
We can, however, build other data structures that represent sorted versions of the data within a hash. An Array, for example:
This gives us the values but you might want to have both the values and their associated keys in a particular order.
Enumerable To The Rescue!
Luckily, Hash has the Enumerable module mixed in which provides us with methods like sort and sort_by. Let's give them a go:
Next, let's use sort_by to get where we want to go (sorting by age):
In this situation we're using sort_by to sort by a specific collection - the values (ages, in our case). Since integers (FixNum objects, in this case) can be compared with <=>, we're good to go. We get a nested array back with one element per hash element in order to preserve the 'ordering'. You can then use Array or other Enumerable methods to work with the result (tip: each* is a good place to start!)
A More Complex Situation
Let's make our hash more complex:
This time we not only have a hash - we have a hash filled with other hashes. What if we want to sort by values within the nested hashes? It's much the same as before, except we address the inner hash during the sort:
Supplement
* Basic : 內建型態與操作 - 雜湊型態
* Basic : 內建型態與操作 - 陣列型態
This is a blog to track what I had learned and share knowledge with all who can take advantage of them
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